Resolver Model for Pspice

Home Forums General Electronics Motor Control Circuits Resolver Model for Pspice

  • This topic is empty.
Viewing 8 posts - 1 through 8 (of 8 total)
  • Author
    Posts
  • #16293
    cpereira
    Guest

    Hi,

    I need a electronic model of a resolver (http://en.wikipedia.org/wiki/Resolver_%28electrical%29) to use in Pspice, because I have to simulate all the electronics to measure the signal provided by this angular sensor.

    Can someone tell me where can I find this model? Or in the latest How can I make it?

    Regards,

    Carlos

    #16386
    Rever75
    Guest

    Hi Carlos,

    The spice model of resolver for PSpice is available only in the last version (16.6.)
    Here you can find articles to try to model the resolver by yourself.

    http://www.sensorsmag.com/sensors/position-presence-proximity/optimizing-motion-control-getting-most-resolvers-1391

    http://www.sensorsmag.com/sensors/position-presence-proximity/optimizing-motion-control-getting-most-resolvers-1391#sidebar1

    If you like, share your results with us

    Regards

    #16387
    cpereira
    Guest

    Hello,

    Thank you very much for your answer.
    I contacted Cadence and they give me the same answer.
    For sure I will try to make the model, and I will share it 🙂
    Regards,
    Carlos
    #16416
    cpereira
    Guest

    Hello Rever75,

    If I have the Z1, Z2 and Z3 of the t-network, is it possible to calculate the RL of Z1, Z2 and Z3?
    Regards,
    Carlos
    #16423
    Rever75
    Guest

    Hi,

    I guess you refer to the resistive component of Z1, Z2, Z3.
    The data sheet should provide you the Zro, Zso, Zrs as a real part and imaginary part. When you calculate Z1, Z2, Z3 with these values, the real parts are the resistive components.

    #16434
    cpereira
    Guest

    Thanks Rever,

    The datasheet provides me with the Rp, RS and the Zro, Zso, Zrs.

    So, I would like to see how to calculate the Z1, Z2 and Z3. To see if my calculi are right.

    Regards,
    Carlos
    #16435
    Rever75
    Guest

    Z3 = √[( Zso ( Zro – Zrs))]

    Z2 = Zso – Z3

    Z1 = Zro – Z3

    #16436
    cpereira
    Guest

    Thanks Rever 🙂

Viewing 8 posts - 1 through 8 (of 8 total)
  • You must be logged in to reply to this topic.